* @dst : destination bitmap
* @src : source bitmap
* @shift : shift by this many bits
- * @bits : bitmap size, in bits
+ * @nbits : bitmap size, in bits
*
* Shifting left (multiplying) means moving bits in the LS -> MS
* direction. Zeros are fed into the vacated LS bit positions
* and those MS bits shifted off the top are lost.
*/
-void __bitmap_shift_left(unsigned long *dst,
- const unsigned long *src, int shift, int bits)
+void __bitmap_shift_left(unsigned long *dst, const unsigned long *src,
+ unsigned int shift, unsigned int nbits)
{
- int k, lim = BITS_TO_LONGS(bits), left = bits % BITS_PER_LONG;
- int off = shift/BITS_PER_LONG, rem = shift % BITS_PER_LONG;
+ int k;
+ unsigned int lim = BITS_TO_LONGS(nbits);
+ unsigned int off = shift/BITS_PER_LONG, rem = shift % BITS_PER_LONG;
for (k = lim - off - 1; k >= 0; --k) {
unsigned long upper, lower;
* word below and make them the bottom rem bits of result.
*/
if (rem && k > 0)
- lower = src[k - 1];
+ lower = src[k - 1] >> (BITS_PER_LONG - rem);
else
lower = 0;
- upper = src[k];
- if (left && k == lim - 1)
- upper &= (1UL << left) - 1;
- dst[k + off] = upper << rem;
- if (rem)
- dst[k + off] |= lower >> (BITS_PER_LONG - rem);
- if (left && k + off == lim - 1)
- dst[k + off] &= (1UL << left) - 1;
+ upper = src[k] << rem;
+ dst[k + off] = lower | upper;
}
if (off)
memset(dst, 0, off*sizeof(unsigned long));