rtsr = RTSR;
/* clear interrupt sources */
RTSR = 0;
- RTSR = (RTSR_AL | RTSR_HZ) & (rtsr >> 2);
+ /* Fix for a nasty initialization problem the in SA11xx RTSR register.
+ * See also the comments in sa1100_rtc_probe(). */
+ if (rtsr & (RTSR_ALE | RTSR_HZE)) {
+ /* This is the original code, before there was the if test
+ * above. This code does not clear interrupts that were not
+ * enabled. */
+ RTSR = (RTSR_AL | RTSR_HZ) & (rtsr >> 2);
+ } else {
+ /* For some reason, it is possible to enter this routine
+ * without interruptions enabled, it has been tested with
+ * several units (Bug in SA11xx chip?).
+ *
+ * This situation leads to an infinite "loop" of interrupt
+ * routine calling and as a result the processor seems to
+ * lock on its first call to open(). */
+ RTSR = RTSR_AL | RTSR_HZ;
+ }
/* clear alarm interrupt if it has occurred */
if (rtsr & RTSR_AL)
platform_set_drvdata(pdev, rtc);
+ /* Fix for a nasty initialization problem the in SA11xx RTSR register.
+ * See also the comments in sa1100_rtc_interrupt().
+ *
+ * Sometimes bit 1 of the RTSR (RTSR_HZ) will wake up 1, which means an
+ * interrupt pending, even though interrupts were never enabled.
+ * In this case, this bit it must be reset before enabling
+ * interruptions to avoid a nonexistent interrupt to occur.
+ *
+ * In principle, the same problem would apply to bit 0, although it has
+ * never been observed to happen.
+ *
+ * This issue is addressed both here and in sa1100_rtc_interrupt().
+ * If the issue is not addressed here, in the times when the processor
+ * wakes up with the bit set there will be one spurious interrupt.
+ *
+ * The issue is also dealt with in sa1100_rtc_interrupt() to be on the
+ * safe side, once the condition that lead to this strange
+ * initialization is unknown and could in principle happen during
+ * normal processing.
+ *
+ * Notice that clearing bit 1 and 0 is accomplished by writting ONES to
+ * the corresponding bits in RTSR. */
+ RTSR = RTSR_AL | RTSR_HZ;
+
return 0;
}