The ordered extents have to fit in memory, so an unsigned long is sufficient.
Signed-off-by: Chris Mason <chris.mason@oracle.com>
* calculates the total size you need to allocate for an ordered sum
* structure spanning 'bytes' in the file
*/
-static inline int btrfs_ordered_sum_size(struct btrfs_root *root, u64 bytes)
+static inline int btrfs_ordered_sum_size(struct btrfs_root *root,
+ unsigned long bytes)
{
unsigned long num_sectors = (bytes + root->sectorsize - 1) /
root->sectorsize;